Which of the following is the negation of the statement "for all $M > 0$,there exists $x \in S$ such that $x \geq M$"?

  • A
    there exists $M > 0$,such that $x \geq M$ for all $x \in S$
  • B
    there exists $M > 0$,there exists $x \in S$ such that $x \geq M$
  • C
    there exists $M > 0$,such that $x < M$ for all $x \in S$
  • D
    there exists $M > 0$,there exists $x \in S$ such that $x < M$

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The expression $((p \wedge q) \vee (p \vee \sim q)) \wedge (\sim p \wedge \sim q)$ is equivalent to

The compound statement $p \wedge (\sim p \wedge q)$ is

Negation of $p \wedge (\sim q \vee \sim r)$ is -

Simplify $(p \vee q) \wedge (p \vee \sim q)$

Statement-$I$: $(p \wedge \sim q) \wedge (\sim p \wedge q)$ is a contradiction.
Statement-$II$: $(p$ $\rightarrow q) \Leftrightarrow (\sim q$ $\rightarrow \sim p)$ is a tautology.

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